I notice that the calculator does not account for the saturation/logarithmic influence of CO2 concentration.

The calculator gives increasing impact for the doubling of CO2 as the concentration increases.

E.g. A=100, B=200 gives 1.49 W/m2

A=200, B=400 gives 1.75 W/m2

A=400, B=800 gives 2.37 W/m2

A=800, B=1600 gives 3.30 W/m2

The current consensus says (incorrectly) that power change should be logarithmic (i.e. the same for each doubling of CO2).

The actual function is actually a logistics function, where CO2 absorbs all available 15um IR and then distributes it through kinetic collisions, leaving nearly all CO2 unsaturated and available to absorb more radiation as it is generated.

This is my calculation on the ability of CO2 to absorb photons.

CO2 Absorbs between 14.2 and 15.8 Micron (550-800cm-1) = 2 micron range

At 20 degrees Celsius, a CO2 molecule has an average kinetic energy of approximately 6.04×10−21 Joules

15 um wave is Energy is 1.3e-20 joule = 8KJ/mol)

15 Micron rad generated from earth surface = 25w/m2=25j/s/m2 x 2micron wide = 50j/s/m2

Photons generated = 50/1.3E-20=3.8E21 photons/s/m2

Moles of Photons per second/m2 = 3.8E21/6E23=0.0063

Atmospheric Molar density at STP 1 mole per 22.4L => 1000L/22.4=44.6429 moles/m3

Moles of CO2/m3 at STP => 44 Moles/m3 *0.04% CO2 = 0.0176 Moles of CO2/m3

Ratio of CO2/Photons +> 0.0176 moles CO2/0.0063 photons =2.8 more CO2 per m3

From Happer

- CO2 has the ability to dissipate radiation through collisions

- CO2 Time to re-emit IR = 0.2s to 1 s

- Mean time between collisions 1ns - 1 billion collisions per second

- Energised CO2 is almost none - 0.000001%

Based on these calculations CO2 will continually absorb nearly all photons within 1m.

Dr Yong Zhong seems to have the best take on this as can be found here

https://www.youtube.com/watch?v=y6LUbfrNtdU&list=PLnHF41Qzzvb6QsxSeiF45GQQMwHgbbVNL&index=9 especially around 9mins.